Integrand size = 17, antiderivative size = 117 \[ \int \frac {\left (a+c x^2\right )^2}{(d+e x)^7} \, dx=-\frac {\left (c d^2+a e^2\right )^2}{6 e^5 (d+e x)^6}+\frac {4 c d \left (c d^2+a e^2\right )}{5 e^5 (d+e x)^5}-\frac {c \left (3 c d^2+a e^2\right )}{2 e^5 (d+e x)^4}+\frac {4 c^2 d}{3 e^5 (d+e x)^3}-\frac {c^2}{2 e^5 (d+e x)^2} \]
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Time = 0.05 (sec) , antiderivative size = 117, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.059, Rules used = {711} \[ \int \frac {\left (a+c x^2\right )^2}{(d+e x)^7} \, dx=-\frac {c \left (a e^2+3 c d^2\right )}{2 e^5 (d+e x)^4}+\frac {4 c d \left (a e^2+c d^2\right )}{5 e^5 (d+e x)^5}-\frac {\left (a e^2+c d^2\right )^2}{6 e^5 (d+e x)^6}-\frac {c^2}{2 e^5 (d+e x)^2}+\frac {4 c^2 d}{3 e^5 (d+e x)^3} \]
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Rule 711
Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {\left (c d^2+a e^2\right )^2}{e^4 (d+e x)^7}-\frac {4 c d \left (c d^2+a e^2\right )}{e^4 (d+e x)^6}+\frac {2 c \left (3 c d^2+a e^2\right )}{e^4 (d+e x)^5}-\frac {4 c^2 d}{e^4 (d+e x)^4}+\frac {c^2}{e^4 (d+e x)^3}\right ) \, dx \\ & = -\frac {\left (c d^2+a e^2\right )^2}{6 e^5 (d+e x)^6}+\frac {4 c d \left (c d^2+a e^2\right )}{5 e^5 (d+e x)^5}-\frac {c \left (3 c d^2+a e^2\right )}{2 e^5 (d+e x)^4}+\frac {4 c^2 d}{3 e^5 (d+e x)^3}-\frac {c^2}{2 e^5 (d+e x)^2} \\ \end{align*}
Time = 0.03 (sec) , antiderivative size = 89, normalized size of antiderivative = 0.76 \[ \int \frac {\left (a+c x^2\right )^2}{(d+e x)^7} \, dx=-\frac {5 a^2 e^4+a c e^2 \left (d^2+6 d e x+15 e^2 x^2\right )+c^2 \left (d^4+6 d^3 e x+15 d^2 e^2 x^2+20 d e^3 x^3+15 e^4 x^4\right )}{30 e^5 (d+e x)^6} \]
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Time = 2.14 (sec) , antiderivative size = 102, normalized size of antiderivative = 0.87
method | result | size |
risch | \(\frac {-\frac {c^{2} x^{4}}{2 e}-\frac {2 c^{2} d \,x^{3}}{3 e^{2}}-\frac {c \left (e^{2} a +c \,d^{2}\right ) x^{2}}{2 e^{3}}-\frac {d c \left (e^{2} a +c \,d^{2}\right ) x}{5 e^{4}}-\frac {5 a^{2} e^{4}+a c \,d^{2} e^{2}+c^{2} d^{4}}{30 e^{5}}}{\left (e x +d \right )^{6}}\) | \(102\) |
gosper | \(-\frac {15 c^{2} x^{4} e^{4}+20 x^{3} c^{2} d \,e^{3}+15 x^{2} a c \,e^{4}+15 x^{2} c^{2} d^{2} e^{2}+6 x a c d \,e^{3}+6 x \,c^{2} d^{3} e +5 a^{2} e^{4}+a c \,d^{2} e^{2}+c^{2} d^{4}}{30 e^{5} \left (e x +d \right )^{6}}\) | \(104\) |
norman | \(\frac {-\frac {c^{2} x^{4}}{2 e}-\frac {2 c^{2} d \,x^{3}}{3 e^{2}}-\frac {\left (e^{3} a c +d^{2} e \,c^{2}\right ) x^{2}}{2 e^{4}}-\frac {d \left (e^{3} a c +d^{2} e \,c^{2}\right ) x}{5 e^{5}}-\frac {5 a^{2} e^{5}+a c \,d^{2} e^{3}+c^{2} d^{4} e}{30 e^{6}}}{\left (e x +d \right )^{6}}\) | \(109\) |
parallelrisch | \(\frac {-15 x^{4} c^{2} e^{5}-20 c^{2} d \,x^{3} e^{4}-15 a c \,e^{5} x^{2}-15 c^{2} d^{2} e^{3} x^{2}-6 a c d \,e^{4} x -6 c^{2} d^{3} e^{2} x -5 a^{2} e^{5}-a c \,d^{2} e^{3}-c^{2} d^{4} e}{30 e^{6} \left (e x +d \right )^{6}}\) | \(109\) |
default | \(-\frac {a^{2} e^{4}+2 a c \,d^{2} e^{2}+c^{2} d^{4}}{6 e^{5} \left (e x +d \right )^{6}}+\frac {4 c^{2} d}{3 e^{5} \left (e x +d \right )^{3}}-\frac {c \left (e^{2} a +3 c \,d^{2}\right )}{2 e^{5} \left (e x +d \right )^{4}}-\frac {c^{2}}{2 e^{5} \left (e x +d \right )^{2}}+\frac {4 c d \left (e^{2} a +c \,d^{2}\right )}{5 e^{5} \left (e x +d \right )^{5}}\) | \(120\) |
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Time = 0.25 (sec) , antiderivative size = 159, normalized size of antiderivative = 1.36 \[ \int \frac {\left (a+c x^2\right )^2}{(d+e x)^7} \, dx=-\frac {15 \, c^{2} e^{4} x^{4} + 20 \, c^{2} d e^{3} x^{3} + c^{2} d^{4} + a c d^{2} e^{2} + 5 \, a^{2} e^{4} + 15 \, {\left (c^{2} d^{2} e^{2} + a c e^{4}\right )} x^{2} + 6 \, {\left (c^{2} d^{3} e + a c d e^{3}\right )} x}{30 \, {\left (e^{11} x^{6} + 6 \, d e^{10} x^{5} + 15 \, d^{2} e^{9} x^{4} + 20 \, d^{3} e^{8} x^{3} + 15 \, d^{4} e^{7} x^{2} + 6 \, d^{5} e^{6} x + d^{6} e^{5}\right )}} \]
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Time = 1.26 (sec) , antiderivative size = 172, normalized size of antiderivative = 1.47 \[ \int \frac {\left (a+c x^2\right )^2}{(d+e x)^7} \, dx=\frac {- 5 a^{2} e^{4} - a c d^{2} e^{2} - c^{2} d^{4} - 20 c^{2} d e^{3} x^{3} - 15 c^{2} e^{4} x^{4} + x^{2} \left (- 15 a c e^{4} - 15 c^{2} d^{2} e^{2}\right ) + x \left (- 6 a c d e^{3} - 6 c^{2} d^{3} e\right )}{30 d^{6} e^{5} + 180 d^{5} e^{6} x + 450 d^{4} e^{7} x^{2} + 600 d^{3} e^{8} x^{3} + 450 d^{2} e^{9} x^{4} + 180 d e^{10} x^{5} + 30 e^{11} x^{6}} \]
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Time = 0.21 (sec) , antiderivative size = 159, normalized size of antiderivative = 1.36 \[ \int \frac {\left (a+c x^2\right )^2}{(d+e x)^7} \, dx=-\frac {15 \, c^{2} e^{4} x^{4} + 20 \, c^{2} d e^{3} x^{3} + c^{2} d^{4} + a c d^{2} e^{2} + 5 \, a^{2} e^{4} + 15 \, {\left (c^{2} d^{2} e^{2} + a c e^{4}\right )} x^{2} + 6 \, {\left (c^{2} d^{3} e + a c d e^{3}\right )} x}{30 \, {\left (e^{11} x^{6} + 6 \, d e^{10} x^{5} + 15 \, d^{2} e^{9} x^{4} + 20 \, d^{3} e^{8} x^{3} + 15 \, d^{4} e^{7} x^{2} + 6 \, d^{5} e^{6} x + d^{6} e^{5}\right )}} \]
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Time = 0.28 (sec) , antiderivative size = 103, normalized size of antiderivative = 0.88 \[ \int \frac {\left (a+c x^2\right )^2}{(d+e x)^7} \, dx=-\frac {15 \, c^{2} e^{4} x^{4} + 20 \, c^{2} d e^{3} x^{3} + 15 \, c^{2} d^{2} e^{2} x^{2} + 15 \, a c e^{4} x^{2} + 6 \, c^{2} d^{3} e x + 6 \, a c d e^{3} x + c^{2} d^{4} + a c d^{2} e^{2} + 5 \, a^{2} e^{4}}{30 \, {\left (e x + d\right )}^{6} e^{5}} \]
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Time = 9.42 (sec) , antiderivative size = 157, normalized size of antiderivative = 1.34 \[ \int \frac {\left (a+c x^2\right )^2}{(d+e x)^7} \, dx=-\frac {\frac {5\,a^2\,e^4+a\,c\,d^2\,e^2+c^2\,d^4}{30\,e^5}+\frac {c^2\,x^4}{2\,e}+\frac {2\,c^2\,d\,x^3}{3\,e^2}+\frac {c\,x^2\,\left (c\,d^2+a\,e^2\right )}{2\,e^3}+\frac {c\,d\,x\,\left (c\,d^2+a\,e^2\right )}{5\,e^4}}{d^6+6\,d^5\,e\,x+15\,d^4\,e^2\,x^2+20\,d^3\,e^3\,x^3+15\,d^2\,e^4\,x^4+6\,d\,e^5\,x^5+e^6\,x^6} \]
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